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Question Number 21815 by gopikrishnan005@gmail.com last updated on 04/Oct/17

sin18^0 =

$${sin}\mathrm{18}^{\mathrm{0}} = \\ $$

Commented by Tinkutara last updated on 04/Oct/17

(((√5)−1)/4)

$$\frac{\sqrt{\mathrm{5}}−\mathrm{1}}{\mathrm{4}} \\ $$

Commented by math solver last updated on 05/Oct/17

emmm .    use identity  sin 3A=3sin A−4sin^3 A

$${emmm}\:.\:\: \\ $$$${use}\:{identity}\:\:\mathrm{sin}\:\mathrm{3}{A}=\mathrm{3sin}\:{A}−\mathrm{4sin}\:^{\mathrm{3}} {A} \\ $$

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