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Question Number 22247 by tapan das last updated on 14/Oct/17

I=∫(√)x^2 +a^2  dx

$$\mathrm{I}=\int\sqrt{}\mathrm{x}^{\mathrm{2}} +\mathrm{a}^{\mathrm{2}} \:\mathrm{dx} \\ $$

Answered by $@ty@m last updated on 14/Oct/17

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