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Question Number 225 by 123456 last updated on 25/Jan/15

u=2i+3j+5k  v=3i+2j−5k  w=−2i+3j+k  find  u∙(v×w)+(u×v)∙(u×w)

u=2i+3j+5kv=3i+2j5kw=2i+3j+kfindu(v×w)+(u×v)(u×w)

Answered by mreddy last updated on 16/Dec/14

v×w= determinant ((i,j,k),(3,2,(−5)),((−2),3,1))=17i+7j+13k  u×w= determinant ((i,j,k),(2,3,5),((−2),3,1))=−12i−12j+12k  u×v= determinant ((i,j,k),(2,3,5),(3,2,(−5)))=−25i+25j−5k  (u×v)∙(u×w)=25×12−25×12−60=−60  u∙(v×w)=34+21+65=120  u∙(v×w)+(u×v)∙(u×w)=120−60=60

v×w=|ijk325231|=17i+7j+13ku×w=|ijk235231|=12i12j+12ku×v=|ijk235325|=25i+25j5k(u×v)(u×w)=25×1225×1260=60u(v×w)=34+21+65=120u(v×w)+(u×v)(u×w)=12060=60

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