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Question Number 225 by 123456 last updated on 25/Jan/15
u=2i+3j+5kv=3i+2j−5kw=−2i+3j+kfindu⋅(v×w)+(u×v)⋅(u×w)
Answered by mreddy last updated on 16/Dec/14
v×w=|ijk32−5−231|=17i+7j+13ku×w=|ijk235−231|=−12i−12j+12ku×v=|ijk23532−5|=−25i+25j−5k(u×v)⋅(u×w)=25×12−25×12−60=−60u⋅(v×w)=34+21+65=120u⋅(v×w)+(u×v)⋅(u×w)=120−60=60
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