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Question Number 22657 by *D¬ B£$T* last updated on 21/Oct/17

A real image 3 times the size of the   object formed by a concave mirror  on a screen. later both the object   & the screen are shifted untill the  image formed is 6 times the size  of the object. if the distnce moved  is 15cm. calculate the focal length  of the mirror.

$${A}\:{real}\:{image}\:\mathrm{3}\:{times}\:{the}\:{size}\:{of}\:{the}\: \\ $$ $${object}\:{formed}\:{by}\:{a}\:{concave}\:{mirror} \\ $$ $${on}\:{a}\:{screen}.\:{later}\:{both}\:{the}\:{object}\: \\ $$ $$\&\:{the}\:{screen}\:{are}\:{shifted}\:{untill}\:{the} \\ $$ $${image}\:{formed}\:{is}\:\mathrm{6}\:{times}\:{the}\:{size} \\ $$ $${of}\:{the}\:{object}.\:{if}\:{the}\:{distnce}\:{moved} \\ $$ $${is}\:\mathrm{15}{cm}.\:{calculate}\:{the}\:{focal}\:{length} \\ $$ $${of}\:{the}\:{mirror}. \\ $$

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