Question Number 22689 by A1B1C1D1 last updated on 21/Oct/17
Answered by ajfour last updated on 25/Oct/17
![=∫_0 ^( 1) [∫_0 ^( 2x) e^x^2 dy]dx =∫_0 ^( 1) 2xe^x^2 dx =(e^x^2 )∣_0 ^1 =e−1 . is it correct?](Q22844.png)
$$=\int_{\mathrm{0}} ^{\:\:\mathrm{1}} \left[\int_{\mathrm{0}} ^{\:\:\mathrm{2}{x}} {e}^{{x}^{\mathrm{2}} } {dy}\right]{dx} \\ $$$$=\int_{\mathrm{0}} ^{\:\:\mathrm{1}} \mathrm{2}{xe}^{{x}^{\mathrm{2}} } {dx}\:=\left({e}^{{x}^{\mathrm{2}} } \right)\mid_{\mathrm{0}} ^{\mathrm{1}} \\ $$$$={e}−\mathrm{1}\:. \\ $$$${is}\:{it}\:{correct}? \\ $$