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Question Number 22745 by Sahib singh last updated on 22/Oct/17

The number of solutions of the   equation  log_(101) log_7 ((√(x+7))+(√x))=0 is

$$\mathrm{The}\:\mathrm{number}\:\mathrm{of}\:\mathrm{solutions}\:\mathrm{of}\:\mathrm{the}\: \\ $$$$\mathrm{equation}\:\:\mathrm{log}_{\mathrm{101}} \mathrm{log}_{\mathrm{7}} \left(\sqrt{{x}+\mathrm{7}}+\sqrt{{x}}\right)=\mathrm{0}\:\mathrm{is} \\ $$

Answered by mrW1 last updated on 22/Oct/17

log_(101) log_7 ((√(x+7))+(√x))=0  ⇒log_7 ((√(x+7))+(√x))=1  ⇒(√(x+7))+(√x)=7  ⇒(√(x+7))=7−(√x)  ⇒x+7=49+x−14(√x)  ⇒(√x)=3  ⇒x=9  ⇒only one solution

$$\mathrm{log}_{\mathrm{101}} \mathrm{log}_{\mathrm{7}} \left(\sqrt{{x}+\mathrm{7}}+\sqrt{{x}}\right)=\mathrm{0} \\ $$$$\Rightarrow\mathrm{log}_{\mathrm{7}} \left(\sqrt{{x}+\mathrm{7}}+\sqrt{{x}}\right)=\mathrm{1} \\ $$$$\Rightarrow\sqrt{{x}+\mathrm{7}}+\sqrt{{x}}=\mathrm{7} \\ $$$$\Rightarrow\sqrt{{x}+\mathrm{7}}=\mathrm{7}−\sqrt{{x}} \\ $$$$\Rightarrow\mathrm{x}+\mathrm{7}=\mathrm{49}+\mathrm{x}−\mathrm{14}\sqrt{\mathrm{x}} \\ $$$$\Rightarrow\sqrt{\mathrm{x}}=\mathrm{3} \\ $$$$\Rightarrow\mathrm{x}=\mathrm{9} \\ $$$$\Rightarrow\mathrm{only}\:\mathrm{one}\:\mathrm{solution} \\ $$

Commented by Sahib singh last updated on 22/Oct/17

thanks

$$\mathrm{thanks} \\ $$

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