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Question Number 22787 by vajpaithegrate@gmail.com last updated on 22/Oct/17

sin^(−1) (sin 10)=10 or 3π−10  Ans is 3π−10   How

$$\mathrm{sin}^{−\mathrm{1}} \left(\mathrm{sin}\:\mathrm{10}\right)=\mathrm{10}\:\mathrm{or}\:\mathrm{3}\pi−\mathrm{10} \\ $$$$\mathrm{Ans}\:\mathrm{is}\:\mathrm{3}\pi−\mathrm{10}\:\:\:\mathrm{How} \\ $$

Commented by mrW1 last updated on 22/Oct/17

by definition the range of sin^(−1)  (x) is [−(π/2), +(π/2)]

$$\mathrm{by}\:\mathrm{definition}\:\mathrm{the}\:\mathrm{range}\:\mathrm{of}\:\mathrm{sin}^{−\mathrm{1}} \:\left(\mathrm{x}\right)\:\mathrm{is}\:\left[−\frac{\pi}{\mathrm{2}},\:+\frac{\pi}{\mathrm{2}}\right] \\ $$

Commented by vajpaithegrate@gmail.com last updated on 22/Oct/17

Thank u sir

$$\mathrm{Thank}\:\mathrm{u}\:\mathrm{sir} \\ $$

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