Question and Answers Forum

All Questions      Topic List

Others Questions

Previous in All Question      Next in All Question      

Previous in Others      Next in Others      

Question Number 22797 by Tinkutara last updated on 22/Oct/17

He^+ in ground state is hit by photon thus exciting electron to second excited state. The energy absorbed in this process is (approx) (1) 2.18 × 10^(−14) J (2) 7.75 × 10^(−18) J (3) 4.5 × 10^(−18) J (4) 5 × 10^(−18) J

$$\mathrm{He}^{+} \:\mathrm{in}\:\mathrm{ground}\:\mathrm{state}\:\mathrm{is}\:\mathrm{hit}\:\mathrm{by}\:\mathrm{photon} \\ $$$$\mathrm{thus}\:\mathrm{exciting}\:\mathrm{electron}\:\mathrm{to}\:\mathrm{second}\:\mathrm{excited} \\ $$$$\mathrm{state}.\:\mathrm{The}\:\mathrm{energy}\:\mathrm{absorbed}\:\mathrm{in}\:\mathrm{this} \\ $$$$\mathrm{process}\:\mathrm{is}\:\left(\mathrm{approx}\right) \\ $$$$\left(\mathrm{1}\right)\:\mathrm{2}.\mathrm{18}\:×\:\mathrm{10}^{−\mathrm{14}} \:\mathrm{J} \\ $$$$\left(\mathrm{2}\right)\:\mathrm{7}.\mathrm{75}\:×\:\mathrm{10}^{−\mathrm{18}} \:\mathrm{J} \\ $$$$\left(\mathrm{3}\right)\:\mathrm{4}.\mathrm{5}\:×\:\mathrm{10}^{−\mathrm{18}} \:\mathrm{J} \\ $$$$\left(\mathrm{4}\right)\:\mathrm{5}\:×\:\mathrm{10}^{−\mathrm{18}} \:\mathrm{J} \\ $$

Answered by = last updated on 22/Oct/17

using balmer′formula : E_(required) = 2.18 ×10^(−18) ×Z^(2 ) {(1/n_1 ^2 ) +(1/n_2 ^2 )} J ⇒ E = 2.18 × 10^(−18) ×2^2 {(1/1)+(1/3^2 )} ⇒E = 7.75×10^(−18) J

$$ \\ $$$${using}\:{balmer}'{formula}\:: \\ $$$${E}_{{required}} \:=\:\mathrm{2}.\mathrm{18}\:×\mathrm{10}^{−\mathrm{18}} ×{Z}^{\mathrm{2}\:} \left\{\frac{\mathrm{1}}{{n}_{\mathrm{1}} ^{\mathrm{2}} }\:+\frac{\mathrm{1}}{{n}_{\mathrm{2}} ^{\mathrm{2}} }\right\}\:{J} \\ $$$$\Rightarrow\:{E}\:=\:\mathrm{2}.\mathrm{18}\:×\:\mathrm{10}^{−\mathrm{18}} ×\mathrm{2}^{\mathrm{2}} \left\{\frac{\mathrm{1}}{\mathrm{1}}+\frac{\mathrm{1}}{\mathrm{3}^{\mathrm{2}} }\right\} \\ $$$$\Rightarrow{E}\:=\:\mathrm{7}.\mathrm{75}×\mathrm{10}^{−\mathrm{18}} {J} \\ $$$$ \\ $$$$ \\ $$$$ \\ $$

Commented by Tinkutara last updated on 22/Oct/17

But the formula is E = 2.18 ×10^(−18) Z^(2 ) ((1/n_1 ^2 )−(1/n_2 ^2 ))J. Why you have written + there?

$$\mathrm{But}\:\mathrm{the}\:\mathrm{formula}\:\mathrm{is} \\ $$$${E}\:=\:\mathrm{2}.\mathrm{18}\:×\mathrm{10}^{−\mathrm{18}} {Z}^{\mathrm{2}\:} \left(\frac{\mathrm{1}}{{n}_{\mathrm{1}} ^{\mathrm{2}} }−\frac{\mathrm{1}}{{n}_{\mathrm{2}} ^{\mathrm{2}} }\right)\mathrm{J}.\:\mathrm{Why} \\ $$$$\mathrm{you}\:\mathrm{have}\:\mathrm{written}\:+\:\mathrm{there}? \\ $$

Commented by = last updated on 22/Oct/17

sorry i meant − sign only and not +

$${sorry}\:{i}\:{meant}\:−\:{sign}\:{only}\:\:{and}\:{not}\:+ \\ $$

Commented by Tinkutara last updated on 22/Oct/17

Then answer would not change?

$$\mathrm{Then}\:\mathrm{answer}\:\mathrm{would}\:\mathrm{not}\:\mathrm{change}? \\ $$

Commented by À. last updated on 22/Oct/17

the calculations have been done according to negative sign

$${the}\:{calculations}\:{have}\:{been}\:{done} \\ $$$${according}\:{to}\:{negative}\:{sign} \\ $$

Commented by Tinkutara last updated on 22/Oct/17

Thank you very much Sir!

$$\mathrm{Thank}\:\mathrm{you}\:\mathrm{very}\:\mathrm{much}\:\mathrm{Sir}! \\ $$

Commented by Rasheed.Sindhi last updated on 22/Oct/17

To the person who gave above answer. What is your id? What id can be thought by “Answer: by on 22/10/17 ”

$$\mathrm{To}\:\mathrm{the}\:\mathrm{person}\:\mathrm{who}\:\mathrm{gave}\:\mathrm{above} \\ $$$$\mathrm{answer}. \\ $$$$\mathrm{What}\:\mathrm{is}\:\mathrm{your}\:\mathrm{id}? \\ $$$$\mathrm{What}\:\mathrm{id}\:\mathrm{can}\:\mathrm{be}\:\mathrm{thought}\:\mathrm{by} \\ $$$$``\mathrm{Answer}:\:\mathrm{by}\:\mathrm{on}\:\mathrm{22}/\mathrm{10}/\mathrm{17}\:'' \\ $$

Commented by Physics lover last updated on 22/Oct/17

lol,i am the person who gave the answer i selected an emoji as my username at first the server accepted but it dint show that emoji here,instead it showed a blank space.

$${lol},{i}\:{am}\:{the}\:{person}\:{who}\:{gave}\:{the}\:{answer} \\ $$$${i}\:{selected}\:{an}\:{emoji}\:{as}\:{my}\:{username} \\ $$$${at}\:{first}\:{the}\:{server}\:{accepted}\:{but} \\ $$$${it}\:{dint}\:{show}\:{that}\:{emoji}\:{here},{instead} \\ $$$${it}\:{showed}\:{a}\:{blank}\:{space}. \\ $$

Commented by Physics lover last updated on 23/Oct/17

thats why you see a space there− answer by“ ” on 22/10/17

$${thats}\:{why}\:{you}\:{see}\:{a}\:{space}\:{there}− \\ $$$${answer}\:{by}``\:\:''\:{on}\:\mathrm{22}/\mathrm{10}/\mathrm{17} \\ $$

Commented by Rasheed.Sindhi last updated on 23/Oct/17

So, in addition to physics you are now experimenting on id! hahaha Anyway thanx to explain.... But there isn′t even a blank space between “Answer: by”and “on 22/10/17”!

$$\mathrm{So},\:\mathrm{in}\:\mathrm{addition}\:\mathrm{to}\:\mathrm{physics}\:\mathrm{you}\:\mathrm{are} \\ $$$$\mathrm{now}\:\mathrm{experimenting}\:\mathrm{on}\:\mathrm{id}!\:\mathrm{hahaha} \\ $$$$\mathrm{Anyway}\:\mathrm{thanx}\:\mathrm{to}\:\mathrm{explain}.... \\ $$$$\mathrm{But}\:\mathrm{there}\:\mathrm{isn}'\mathrm{t}\:\mathrm{even}\:\mathrm{a}\:\mathrm{blank}\:\mathrm{space}\:\mathrm{between} \\ $$$$``\mathrm{Answer}:\:\mathrm{by}''\mathrm{and}\:``\mathrm{on}\:\mathrm{22}/\mathrm{10}/\mathrm{17}''! \\ $$

Commented by Physics lover last updated on 23/Oct/17

well,there is one space there.lol

$${well},{there}\:{is}\:{one}\:{space}\:{there}.{lol} \\ $$

Commented by Physics lover last updated on 23/Oct/17

you would also see a question mark symbol in the next . i used the username “π.”there It displayed question mark instead of π and showed the dot as it is

$${you}\:{would}\:{also}\:{see}\:{a}\:{question}\: \\ $$$${mark}\:{symbol}\:{in}\:{the}\:{next}\:. \\ $$$${i}\:{used}\:{the}\:{username}\:``\pi.''{there} \\ $$$${It}\:{displayed}\:{question}\:{mark}\:{instead} \\ $$$${of}\:\pi\:{and}\:{showed}\:{the}\:{dot}\:{as}\:{it}\:{is} \\ $$

Commented by Physics lover last updated on 23/Oct/17

you can also repeat the experiment. you will get the same result. ;)

$${you}\:{can}\:{also}\:{repeat}\:{the}\:{experiment}. \\ $$$$\left.{you}\:{will}\:{get}\:\:{the}\:{same}\:{result}.\:;\right) \\ $$$$ \\ $$

Commented by Rasheed.Sindhi last updated on 23/Oct/17

Anyway you can write a monograph paper on IDology now. lol.

$$\mathrm{Anyway}\:\mathrm{you}\:\mathrm{can}\:\mathrm{write}\:\mathrm{a}\:\mathrm{monograph} \\ $$$$\mathrm{paper}\:\mathrm{on}\:\boldsymbol{\mathrm{ID}}\mathrm{ology}\:\mathrm{now}.\:{lol}. \\ $$

Commented by Rasheed.Sindhi last updated on 23/Oct/17

This will be a new subject introduced by you. hahaha.. lol.

$$\mathrm{This}\:\mathrm{will}\:\mathrm{be}\:\mathrm{a}\:\mathrm{new}\:\mathrm{subject}\:\mathrm{introduced} \\ $$$$\mathrm{by}\:\mathrm{you}.\:\mathrm{hahaha}..\:{lol}. \\ $$

Commented by Physics lover last updated on 23/Oct/17

lol

$$ \\ $$$${lol} \\ $$$$ \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com