Question Number 22993 by Tinkutara last updated on 24/Oct/17
$$\mathrm{For}\:\mathrm{which}\:\mathrm{of}\:\mathrm{the}\:\mathrm{following},\:\mathrm{the} \\ $$$$\mathrm{hydration}\:\mathrm{energy}\:\mathrm{of}\:\mathrm{Mg}^{\mathrm{2}+} \:\mathrm{is}\:\mathrm{larger}? \\ $$$$\left(\mathrm{1}\right)\:\mathrm{Na}^{+} \\ $$$$\left(\mathrm{2}\right)\:\mathrm{Al}^{\mathrm{3}+} \\ $$$$\left(\mathrm{3}\right)\:\mathrm{Be}^{\mathrm{2}+} \\ $$$$\left(\mathrm{4}\right)\:\mathrm{Cr}^{\mathrm{3}+} . \\ $$
Answered by math solver last updated on 24/Oct/17
$${Na}^{+} \:{because}\:{hydration}\:{energy}\: \\ $$$${depends}\:{on}\:{charge}\:{and}\:{size}. \\ $$$$\left\{{charge}\:{more}\:{preference}\:{than}\:{size}\right\} \\ $$$${and}\:{out}\:{of}\:\mathrm{4}\:{only}\:{Na}^{+} \:{has}\:+\mathrm{1}\:{charge}. \\ $$$${more}\:{charge}\:,\:{more}\:{hydration}\:{energy} \\ $$$${and}\:{vice}\:{versa}\:{for}\:{size}\:..... \\ $$
Commented by Tinkutara last updated on 27/Oct/17
$$\mathrm{Thank}\:\mathrm{you}\:\mathrm{Sir}. \\ $$
Commented by math solver last updated on 25/Oct/17
$${read}\:{the}\:{question}\:{properly}\:!\: \\ $$$${you}\:{are}\:{getting}\:{it}\:{wrong}\:...... \\ $$$${ok},\:{so}\:{it}\:{is}\:{asking}\:{in}\:{comparing}\:{with} \\ $$$${which}\:{element}\:{mg}^{\mathrm{2}+} \:{has}\:{higher}\: \\ $$$${hydration}\:{energy}\:\:... \\ $$$$ \\ $$
Answered by Tinkutara last updated on 27/Oct/17
Commented by math solver last updated on 27/Oct/17
$$\mathrm{yaaa}\:!\mathrm{this}\:\mathrm{is}\:\mathrm{what}\:\mathrm{I}\:\mathrm{told}\:\mathrm{you}\:... \\ $$