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Question Number 23020 by ANTARES_VY last updated on 25/Oct/17

∫_1 ^3 ((4x+1)/(2x^2 +x−2))dx=?

$$\underset{\mathrm{1}} {\overset{\mathrm{3}} {\int}}\frac{\mathrm{4}\boldsymbol{\mathrm{x}}+\mathrm{1}}{\mathrm{2}\boldsymbol{\mathrm{x}}^{\mathrm{2}} +\boldsymbol{\mathrm{x}}−\mathrm{2}}\boldsymbol{\mathrm{dx}}=? \\ $$

Commented by Joel577 last updated on 25/Oct/17

it′s already done

$${it}'{s}\:{already}\:{done} \\ $$

Commented by ANTARES_VY last updated on 25/Oct/17

calculate

$$\boldsymbol{\mathrm{calculate}} \\ $$

Commented by ANTARES_VY last updated on 25/Oct/17

calculate

$$\boldsymbol{\mathrm{calculate}} \\ $$

Answered by $@ty@m last updated on 27/Oct/17

=[ln (2x^2 +x−2)]_1 ^3   =ln 19−ln 1  =ln 19

$$=\left[\mathrm{ln}\:\left(\mathrm{2}{x}^{\mathrm{2}} +{x}−\mathrm{2}\right)\underset{\mathrm{1}} {\overset{\mathrm{3}} {\right]}} \\ $$$$=\mathrm{ln}\:\mathrm{19}−\mathrm{ln}\:\mathrm{1} \\ $$$$=\mathrm{ln}\:\mathrm{19} \\ $$

Commented by ajfour last updated on 26/Oct/17

ln 19

$$\mathrm{ln}\:\mathrm{19} \\ $$

Commented by $@ty@m last updated on 27/Oct/17

Thanks for correction...

$${Thanks}\:{for}\:{correction}... \\ $$

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