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Question Number 23130 by Tinkutara last updated on 26/Oct/17

A baloon filled with helium rises against  gravity increasing its potential energy.  The speed of the baloon also increases  as it rises. How do you reconcile this  with the law of conservation of  mechanical energy? You can neglect  viscous drag of air and assume that  density of air is constant.

$$\mathrm{A}\:\mathrm{baloon}\:\mathrm{filled}\:\mathrm{with}\:\mathrm{helium}\:\mathrm{rises}\:\mathrm{against} \\ $$$$\mathrm{gravity}\:\mathrm{increasing}\:\mathrm{its}\:\mathrm{potential}\:\mathrm{energy}. \\ $$$$\mathrm{The}\:\mathrm{speed}\:\mathrm{of}\:\mathrm{the}\:\mathrm{baloon}\:\mathrm{also}\:\mathrm{increases} \\ $$$$\mathrm{as}\:\mathrm{it}\:\mathrm{rises}.\:\mathrm{How}\:\mathrm{do}\:\mathrm{you}\:\mathrm{reconcile}\:\mathrm{this} \\ $$$$\mathrm{with}\:\mathrm{the}\:\mathrm{law}\:\mathrm{of}\:\mathrm{conservation}\:\mathrm{of} \\ $$$$\mathrm{mechanical}\:\mathrm{energy}?\:\mathrm{You}\:\mathrm{can}\:\mathrm{neglect} \\ $$$$\mathrm{viscous}\:\mathrm{drag}\:\mathrm{of}\:\mathrm{air}\:\mathrm{and}\:\mathrm{assume}\:\mathrm{that} \\ $$$$\mathrm{density}\:\mathrm{of}\:\mathrm{air}\:\mathrm{is}\:\mathrm{constant}. \\ $$

Commented by ajfour last updated on 26/Oct/17

Internal energy of confined  helium in baloon decreases..

$${Internal}\:{energy}\:{of}\:{confined} \\ $$$${helium}\:{in}\:{baloon}\:{decreases}.. \\ $$

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