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Question Number 23243 by paro123 last updated on 27/Oct/17

$$2^{\mathrm{n}-1}\sin \mathrm{a}\times \sin 2\mathrm{a}\times \sin 3\mathrm{a}\times ......\times \sin (\mathrm{n}-1)\mathrm{a}=\mathrm{n}\mathrm{why}?$$

Commented by mrW1 last updated on 28/Oct/17

$$\mathrm{this}\mathrm{statement}\mathrm{is}\mathrm{wrong}!$$$$$$$$\mathrm{you}\mathrm{can}\mathrm{find}\mathrm{a}\mathrm{lot}\mathrm{of}\mathrm{examples}:$$$$\mathrm{if}\mathrm{n}=3:$$$$2^{3-1}\sin \mathrm{a}\times \sin 2\mathrm{a}=4\sin \mathrm{a}\times \sin 2\mathrm{a}\ne 3$$$$$$$$\mathrm{if}\mathrm{a}=\pm \pi \mathrm{or}\pm \frac{\pi }{2}\mathrm{or}\pm \frac{\pi }{3}\mathrm{or}\pm \frac{\pi }{4}.....:$$$$2^{\mathrm{n}-1}\sin \mathrm{a}\times \sin 2\mathrm{a}\times \sin 3\mathrm{a}\times ......\times \sin (\mathrm{n}-1)\mathrm{a}=0\ne \mathrm{n}$$

Commented by paro123 last updated on 28/Oct/17

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