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Question Number 23317 by tapan das last updated on 28/Oct/17

∫sin^3 x cos x dx

$$\int\mathrm{sin}\:^{\mathrm{3}} \mathrm{x}\:\mathrm{cos}\:\mathrm{x}\:\mathrm{dx} \\ $$

Answered by mrW1 last updated on 28/Oct/17

=∫sin^3  x dsin x  =((sin^4  x)/4)+C

$$=\int\mathrm{sin}^{\mathrm{3}} \:\mathrm{x}\:\mathrm{dsin}\:\mathrm{x} \\ $$$$=\frac{\mathrm{sin}^{\mathrm{4}} \:\mathrm{x}}{\mathrm{4}}+\mathrm{C} \\ $$

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