Question and Answers Forum

All Questions      Topic List

Others Questions

Previous in All Question      Next in All Question      

Previous in Others      Next in Others      

Question Number 23381 by Tinkutara last updated on 29/Oct/17

A women swimming upstream is not  moving with respect to the ground. Is  she doing any work, if she stops  swimming and merely floats is work  done on her?

$$\mathrm{A}\:\mathrm{women}\:\mathrm{swimming}\:\mathrm{upstream}\:\mathrm{is}\:\mathrm{not} \\ $$$$\mathrm{moving}\:\mathrm{with}\:\mathrm{respect}\:\mathrm{to}\:\mathrm{the}\:\mathrm{ground}.\:\mathrm{Is} \\ $$$$\mathrm{she}\:\mathrm{doing}\:\mathrm{any}\:\mathrm{work},\:\mathrm{if}\:\mathrm{she}\:\mathrm{stops} \\ $$$$\mathrm{swimming}\:\mathrm{and}\:\mathrm{merely}\:\mathrm{floats}\:\mathrm{is}\:\mathrm{work} \\ $$$$\mathrm{done}\:\mathrm{on}\:\mathrm{her}? \\ $$

Answered by ajfour last updated on 29/Oct/17

Unless the sum of kinetic and  potential energy changes, no  work is done. So, No for both   cases; for the first displacement  is zero (she resists motion of  flow as much as she contibutes  to it). In the second there is no  force to imcrease her kinetic  energy.

$${Unless}\:{the}\:{sum}\:{of}\:{kinetic}\:{and} \\ $$$${potential}\:{energy}\:{changes},\:{no} \\ $$$${work}\:{is}\:{done}.\:{So},\:{No}\:{for}\:{both}\: \\ $$$${cases};\:{for}\:{the}\:{first}\:{displacement} \\ $$$${is}\:{zero}\:\left({she}\:{resists}\:{motion}\:{of}\right. \\ $$$${flow}\:{as}\:{much}\:{as}\:{she}\:{contibutes} \\ $$$$\left.{to}\:{it}\right).\:{In}\:{the}\:{second}\:{there}\:{is}\:{no} \\ $$$${force}\:{to}\:{imcrease}\:{her}\:{kinetic} \\ $$$${energy}. \\ $$

Commented by Tinkutara last updated on 30/Oct/17

Thank you very much Sir!

$$\mathrm{Thank}\:\mathrm{you}\:\mathrm{very}\:\mathrm{much}\:\mathrm{Sir}! \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com