Question and Answers Forum

All Questions      Topic List

Differentiation Questions

Previous in All Question      Next in All Question      

Previous in Differentiation      Next in Differentiation      

Question Number 23428 by gopikrishnan005@gmail.com last updated on 30/Oct/17

the curve ay^2 =x^2 (3a−x) cuts the y-axis at

$${the}\:{curve}\:{ay}^{\mathrm{2}} ={x}^{\mathrm{2}} \left(\mathrm{3}{a}−{x}\right)\:{cuts}\:{the}\:{y}-{axis}\:{at} \\ $$

Answered by $@ty@m last updated on 30/Oct/17

orogin

$${orogin} \\ $$

Answered by FilupES last updated on 31/Oct/17

y^2 =(x^2 /a)(3a−x)  cuts origin when y=0  (note y^2 =y=0)     ∴(x^2 /a)(3a−x)=0  x=0  and x=3a

$${y}^{\mathrm{2}} =\frac{{x}^{\mathrm{2}} }{{a}}\left(\mathrm{3}{a}−{x}\right) \\ $$$$\mathrm{cuts}\:\mathrm{origin}\:\mathrm{when}\:{y}=\mathrm{0} \\ $$$$\left(\mathrm{note}\:{y}^{\mathrm{2}} ={y}=\mathrm{0}\right) \\ $$$$\: \\ $$$$\therefore\frac{{x}^{\mathrm{2}} }{{a}}\left(\mathrm{3}{a}−{x}\right)=\mathrm{0} \\ $$$${x}=\mathrm{0} \\ $$$$\mathrm{and}\:{x}=\mathrm{3}{a} \\ $$

Commented by mrW1 last updated on 31/Oct/17

I think he wants the cut points on y−axis,  i.e. x=0

$$\mathrm{I}\:\mathrm{think}\:\mathrm{he}\:\mathrm{wants}\:\mathrm{the}\:\mathrm{cut}\:\mathrm{points}\:\mathrm{on}\:\mathrm{y}−\mathrm{axis}, \\ $$$$\mathrm{i}.\mathrm{e}.\:\mathrm{x}=\mathrm{0} \\ $$

Commented by FilupES last updated on 31/Oct/17

thanks, i missread the question

$$\mathrm{thanks},\:\mathrm{i}\:\mathrm{missread}\:\mathrm{the}\:\mathrm{question} \\ $$

Commented by FilupES last updated on 31/Oct/17

y axis when x=0  ∴y=0

$${y}\:{axis}\:\mathrm{when}\:{x}=\mathrm{0} \\ $$$$\therefore{y}=\mathrm{0} \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com