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Question Number 23645 by Tinkutara last updated on 03/Nov/17

Ethylene on combustion gives carbon  dioxide and water. Its enthalpy of  combustion is 1410 kJ/mol. If the  enthalpy of formation of CO_2  and H_2 O  are 393.3 kJ and 286.2 kJ respectively.  Calculate the enthalpy of formation of  ethylene.

$$\mathrm{Ethylene}\:\mathrm{on}\:\mathrm{combustion}\:\mathrm{gives}\:\mathrm{carbon} \\ $$$$\mathrm{dioxide}\:\mathrm{and}\:\mathrm{water}.\:\mathrm{Its}\:\mathrm{enthalpy}\:\mathrm{of} \\ $$$$\mathrm{combustion}\:\mathrm{is}\:\mathrm{1410}\:\mathrm{kJ}/\mathrm{mol}.\:\mathrm{If}\:\mathrm{the} \\ $$$$\mathrm{enthalpy}\:\mathrm{of}\:\mathrm{formation}\:\mathrm{of}\:\mathrm{CO}_{\mathrm{2}} \:\mathrm{and}\:\mathrm{H}_{\mathrm{2}} \mathrm{O} \\ $$$$\mathrm{are}\:\mathrm{393}.\mathrm{3}\:\mathrm{kJ}\:\mathrm{and}\:\mathrm{286}.\mathrm{2}\:\mathrm{kJ}\:\mathrm{respectively}. \\ $$$$\mathrm{Calculate}\:\mathrm{the}\:\mathrm{enthalpy}\:\mathrm{of}\:\mathrm{formation}\:\mathrm{of} \\ $$$$\mathrm{ethylene}. \\ $$

Commented by Tinkutara last updated on 03/Nov/17

Book says: +51 kJ mol^(−1)

$$\mathrm{Book}\:\mathrm{says}:\:+\mathrm{51}\:\mathrm{kJ}\:\mathrm{mol}^{−\mathrm{1}} \\ $$

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