Question Number 23752 by pombekali last updated on 05/Nov/17
$$\int_{\mathrm{1}} ^{\mathrm{2}} {x}^{\mathrm{3}} +\mathrm{1}=? \\ $$
Answered by Joel577 last updated on 05/Nov/17
![[(1/4)x^4 + x]_1 ^2 = ((1/4)(2^4 ) + 2) − ((1/4)(1^4 ) + 1) = 6 − (5/4) = ((19)/4)](Q23753.png)
$$\left[\frac{\mathrm{1}}{\mathrm{4}}{x}^{\mathrm{4}} \:+\:{x}\right]_{\mathrm{1}} ^{\mathrm{2}} \:=\:\left(\frac{\mathrm{1}}{\mathrm{4}}\left(\mathrm{2}^{\mathrm{4}} \right)\:+\:\mathrm{2}\right)\:−\:\left(\frac{\mathrm{1}}{\mathrm{4}}\left(\mathrm{1}^{\mathrm{4}} \right)\:+\:\mathrm{1}\right) \\ $$$$=\:\mathrm{6}\:−\:\frac{\mathrm{5}}{\mathrm{4}}\:=\:\frac{\mathrm{19}}{\mathrm{4}} \\ $$