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Question Number 24524 by mondodotto@gmail.com last updated on 20/Nov/17

Answered by mrW1 last updated on 20/Nov/17

$$x⩾0$$$$2(x+1)\log 9=x^{\frac{1}{2}}$$$${\left(2\log 9\right)}^2{(x+1)}^2=x$$$${\left(2\log 9\right)}^2{(x+1)}^2-(x+1)+1=0$$$$D=1-4{\left(2\log 9\right)}^2<0$$$$\Rightarrow thereisnorealsolution!$$$$$$$$x+1=\frac{1\pm i\sqrt{4{\left(2\log 9\right)}^2-1}}{2{\left(2\log 9\right)}^2}$$$$x=\frac{1\pm i\sqrt{4{\left(2\log 9\right)}^2-1}}{2{\left(2\log 9\right)}^2}-1$$

Commented by Rasheed.Sindhi last updated on 20/Nov/17

$$\mathcal{V}.\mathcal{N}ice\mathcal{S}ir!$$

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