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Question Number 25280 by NECx last updated on 07/Dec/17

Find the limit off(x) _(x→4) =(((x+2)/(x^2 −4)))

$${Find}\:{the}\:{limit}\:{off}\left({x}\right)\underset{{x}\rightarrow\mathrm{4}} {\:}=\left(\frac{{x}+\mathrm{2}}{{x}^{\mathrm{2}} −\mathrm{4}}\right) \\ $$

Answered by Rasheed.Sindhi last updated on 07/Dec/17

Since limit of the denominator≠0  So  lim_(x→4) ((x+2)/(x^2 −4))=((lim_(x→4) (x+2))/(lim_(x→4) (x^2 −4)))=((4+2)/(16−4))=(1/2)

$$\mathrm{Since}\:\mathrm{limit}\:\mathrm{of}\:\mathrm{the}\:\mathrm{denominator}\neq\mathrm{0} \\ $$$$\mathrm{So} \\ $$$$\underset{\mathrm{x}\rightarrow\mathrm{4}} {\mathrm{lim}}\frac{\mathrm{x}+\mathrm{2}}{\mathrm{x}^{\mathrm{2}} −\mathrm{4}}=\frac{\underset{\mathrm{x}\rightarrow\mathrm{4}} {\mathrm{lim}}\left(\mathrm{x}+\mathrm{2}\right)}{\underset{\mathrm{x}\rightarrow\mathrm{4}} {\mathrm{lim}}\left(\mathrm{x}^{\mathrm{2}} −\mathrm{4}\right)}=\frac{\mathrm{4}+\mathrm{2}}{\mathrm{16}−\mathrm{4}}=\frac{\mathrm{1}}{\mathrm{2}} \\ $$

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