A man pushes a box of 40kg up an incline of 15°.If the man applied a horizontal force 200N and the box moves up the plane a distance of 20m at a constant velocity and the coefficient of friction is 0.10, find a)workdone by the man on the box b)workdone against friction.


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Question Number 25308 by NECx last updated on 08/Dec/17

$A m a n p u s h e s a b o x o f 40 k g u p a n$ $i n c l i n e o f 15 ° . I f t h e m a n a p p l i e d$ $a h o r i z o n t a l f o r c e 200 N a n d t h e$ $b o x m o v e s u p t h e p l a n e a d i s t a n c e$ $o f 20 m a t a c o n s t a n t v e l o c i t y a n d$ $t h e c o e f f i c i e n t o f f r i c t i o n i s 0.10,$ $f i n d$ $a) w o r k d o n e b y t h e m a n o n t h e$ $b o x$ $b) w o r k d o n e a g a i n s t f r i c t i o n .$
	Answered by jota+ last updated on 08/Dec/17

	$θ = 15 F = 200 N s = 20 m$ $m = 40 k g μ = 0.10$ $F_{s} = F \cos θ - m g \sin θ - μ N .$ $N = m g \cos θ + F \sin θ$ $a) W = F_{s} s$ $b) W = - μ N s$
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