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Question Number 25334 by arvindbrar26068@gmail.com last updated on 08/Dec/17

$$\mathrm{Three}\mathrm{dice}\mathrm{are}\mathrm{rolled}.\mathrm{The}\mathrm{number}\mathrm{of}$$$$\mathrm{possible}\mathrm{outcomes}\mathrm{in}\mathrm{which}\mathrm{at}\mathrm{least}$$$$\mathrm{one}\mathrm{die}\mathrm{shows}5\mathrm{is}$$

Answered by ajfour last updated on 08/Dec/17

$$coeff.of{x}^1+coeff.of{x}^2+$$$$coeff.of{x}^{3}in{(5+x)}^3$$$$=75+15+1=91.$$$$or$$$$=216-125=91.$$

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