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Question Number 25600 by Mcfaithal last updated on 11/Dec/17

$$\mathrm{A}\mathrm{block}\mathrm{pulled}\mathrm{along}\mathrm{a}\mathrm{horizontal}\mathrm{floo}$$$$\mathrm{by}\mathrm{a}\mathrm{horizontal}\mathrm{rope}.$$$$\mathrm{The}\mathrm{tension}\mathrm{in}\mathrm{the}\mathrm{rope}\mathrm{is}500\mathrm{N}\mathrm{and}\mathrm{the}$$$$\mathrm{blocks}\mathrm{moves}\mathrm{at}\mathrm{a}\mathrm{constant}\mathrm{speed}\mathrm{of}2.{75\mathrm{ms}}^{-1.}$$$$\mathrm{Find}\mathrm{the}\mathrm{work}\mathrm{done}\mathrm{by}\mathrm{the}\mathrm{tension}\mathrm{in}40\mathrm{s}$$$$\mathrm{and}\mathrm{also}\mathrm{find}\mathrm{the}\mathrm{power}\mathrm{applied}\mathrm{by}\mathrm{the}\mathrm{tension}.$$$$\mathrm{GUYS}\mathrm{PLS}\mathrm{HELP}$$

Answered by jota@ last updated on 12/Dec/17

$$W=Fs=Fvt=\left(500\right)(2.75)\left(40\right)J$$$$P=W/t=500\times 2.75W$$

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