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Question Number 25611 by nnnavendu last updated on 12/Dec/17

if cosh(u+iv)=x+iy , show that  (x^2 /(cosh^2 u))+(y^2 /(sinh^2 u))=1  and  (x^2 /(cosh^2 v))−(y^2 /(sinh^2 v))=1    where    sinhx and coshx    hhyperbolcfunction

$${if}\:{cosh}\left({u}+{iv}\right)={x}+{iy}\:,\:{show}\:{that} \\ $$$$\frac{{x}^{\mathrm{2}} }{{cosh}^{\mathrm{2}} {u}}+\frac{{y}^{\mathrm{2}} }{{sinh}^{\mathrm{2}} {u}}=\mathrm{1}\:\:{and}\:\:\frac{{x}^{\mathrm{2}} }{{cosh}^{\mathrm{2}} {v}}−\frac{{y}^{\mathrm{2}} }{{sinh}^{\mathrm{2}} {v}}=\mathrm{1} \\ $$$$ \\ $$$${where}\:\:\:\:{sinhx}\:{and}\:{coshx}\:\:\:\:{hhyperbolcfunction} \\ $$

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