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Question Number 25623 by Sunilll last updated on 12/Dec/17
solveforAandBif2A+B[636−2]and3A+2B[1005]
Answered by mrW1 last updated on 12/Dec/17
2A+B=C...(i)3A+2B=D...(ii)2(i)−(ii):⇒A=2C−D=[11612−9]⇒B=C−2A=[−16−9−1816]
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