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Question Number 25723 by Joel578 last updated on 13/Dec/17

$$\mathrm{Given}{a}_1,a_2,...,a_n\mathrm{are}\mathrm{non}-\mathrm{negative}$$$$\mathrm{integers}\mathrm{and}\mathrm{satisfy}$$$$\frac{1}{2^{a_1}}+\frac{1}{2^{a_2}}+...+\frac{1}{2^{a_n}}=\frac{1}{3^{a_1}}+\frac{2}{3^{a_2}}+...+\frac{n}{3^{a_n}}=1$$$$\mathrm{If}n\mathrm{is}\mathrm{positive}\mathrm{integer},\mathrm{find}\mathrm{all}\mathrm{possible}\mathrm{solution}$$$$\mathrm{of}n$$

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