Question and Answers Forum

All Questions      Topic List

UNKNOWN Questions

Previous in All Question      Next in All Question      

Previous in UNKNOWN      Next in UNKNOWN      

Question Number 25985 by Vignesh vkj last updated on 17/Dec/17

In a △ABC, a cot A+ b cot B+c cot C =

$$\mathrm{In}\:\mathrm{a}\:\bigtriangleup{ABC},\:{a}\:\mathrm{cot}\:{A}+\:{b}\:\mathrm{cot}\:{B}+{c}\:\mathrm{cot}\:{C}\:= \\ $$

Answered by ajfour last updated on 17/Dec/17

Σacot A =Σ(√(4R^2 −a^2 ))  R is the circumradius .

$$\Sigma{a}\mathrm{cot}\:{A}\:=\Sigma\sqrt{\mathrm{4}{R}^{\mathrm{2}} −{a}^{\mathrm{2}} } \\ $$$${R}\:{is}\:{the}\:{circumradius}\:. \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com