Question Number 26042 by sanjib bibhar last updated on 18/Dec/17 | ||
$${ax}^{\mathrm{2}} −{bx}=\mathrm{0} \\ $$ | ||
Commented by sanjib bibhar last updated on 19/Dec/17 | ||
$${thanks} \\ $$ | ||
Commented by Rasheed.Sindhi last updated on 18/Dec/17 | ||
$${ax}^{\mathrm{2}} −{bx}=\mathrm{0} \\ $$$${x}\left({ax}−{b}\right)=\mathrm{0} \\ $$$${x}=\mathrm{0}\:\mid\:{ax}−{b}=\mathrm{0} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\mid\:{x}=\frac{{b}}{{a}}\:\:;\:{a}\neq\mathrm{0} \\ $$ | ||