Question Number 26200 by mubeen897@hotmail.com last updated on 22/Dec/17
Answered by ajfour last updated on 22/Dec/17
![(0.2×10)+10+(0.2×20)−30+ 0.5R+(0.5×10)=0 ⇒ 2+10+4−30+0.5R+[×]+5=0 or 0.5R = 9 ⇒ R=18Ω .](Q26208.png)
$$\left(\mathrm{0}.\mathrm{2}×\mathrm{10}\right)+\mathrm{10}+\left(\mathrm{0}.\mathrm{2}×\mathrm{20}\right)−\mathrm{30}+ \\ $$$$\:\:\:\:\:\:\:\mathrm{0}.\mathrm{5}{R}+\left(\mathrm{0}.\mathrm{5}×\mathrm{10}\right)=\mathrm{0} \\ $$$$\Rightarrow\:\mathrm{2}+\mathrm{10}+\mathrm{4}−\mathrm{30}+\mathrm{0}.\mathrm{5}{R}+\left[×\right]+\mathrm{5}=\mathrm{0} \\ $$$${or}\:\:\:\:\:\mathrm{0}.\mathrm{5}{R}\:=\:\mathrm{9}\:\:\:\Rightarrow\:\:\:{R}=\mathrm{18}\Omega\:. \\ $$
Commented by mubeen897@hotmail.com last updated on 22/Dec/17
$${Sorry}\:{Bro}\:{answer}\:{is}\:\mathrm{18}\:{Ohms}\:{I}\:{really}\:{tried}\:{to}\:{but}\:{its}\:{trickyy} \\ $$
Commented by mubeen897@hotmail.com last updated on 22/Dec/17
$${But}\:{Nice}\:{Tryy} \\ $$