Question Number 26298 by d.monhbayr@gmail.com last updated on 24/Dec/17
$${y}=\mathrm{sin}\:^{\mathrm{4}} {x} \\ $$$${y}'=?\:{differential} \\ $$
Commented by prakash jain last updated on 24/Dec/17
$$\frac{{d}}{{dx}}\mathrm{sin}^{\mathrm{4}} {x} \\ $$$$=\frac{{d}}{{d}\left(\mathrm{sin}\:{x}\right)}\mathrm{sin}^{\mathrm{4}} {x}\centerdot\frac{{d}\mathrm{sin}\:{x}}{{dx}} \\ $$$$=\mathrm{4sin}^{\mathrm{3}} {x}\mathrm{cos}\:{x} \\ $$
Commented by abdo imad last updated on 23/Dec/17
$$\frac{{dy}}{{dx}}\:=\:\mathrm{4}\:{cosx}\:{sin}^{\mathrm{3}} {x} \\ $$