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Question Number 26389 by ajfour last updated on 24/Dec/17

Commented by ajfour last updated on 24/Dec/17

$$r+\frac{1}{r^2}=c;or\cos \theta +\sec {}^2\theta =c$$$$\Rightarrow ifx=\frac{1}{r}then{x}^2+\frac{1}{x}=c$$$$or{x}^3-cx+1=0$$$$findsignificanceof$$$$△=\sqrt{{\left(\frac{1}{2}\right)}^2+{(-\frac{c}{3})}^3}$$$$inthediagramabove.$$

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