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Question Number 26463 by sanyam soni last updated on 25/Dec/17

∫_0 ^(2π) cos^2 θsin θdθ

$$\int_{\mathrm{0}} ^{\mathrm{2}\pi} \mathrm{cos}^{\mathrm{2}} \theta\mathrm{sin}\:\theta{d}\theta \\ $$

Commented by abdo imad last updated on 25/Dec/17

= −(1/3)cos_θ ^3  ]_(θ=0) ^(θ=2π) = −(1/3).0=0

$$\left.=\:−\frac{\mathrm{1}}{\mathrm{3}}{cos}_{\theta} ^{\mathrm{3}} \:\right]_{\theta=\mathrm{0}} ^{\theta=\mathrm{2}\pi} =\:−\frac{\mathrm{1}}{\mathrm{3}}.\mathrm{0}=\mathrm{0} \\ $$

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