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Question Number 26498 by keshabthagunna3@gmail.com last updated on 26/Dec/17

$$\mathrm{If}(5x+7y):(3x+11y)=2:3,\mathrm{then}$$$$x:y=\mathrm{\_}\mathrm{\_}\mathrm{\_}\mathrm{\_}.$$

Answered by Rasheed.Sindhi last updated on 26/Dec/17

$$\frac{5\mathrm{x}+7\mathrm{y}}{3\mathrm{x}+11\mathrm{y}}=\frac{2}{3}$$$$\frac{(5\mathrm{x}+7\mathrm{y})/\mathrm{y}}{(3\mathrm{x}+11\mathrm{y})/\mathrm{y}}=\frac{2}{3}$$$$\frac{5\left(\frac{\mathrm{x}}{\mathrm{y}}\right)+7}{3\left(\frac{\mathrm{x}}{\mathrm{y}}\right)+11}=\frac{2}{3}$$$$15\left(\frac{\mathrm{x}}{\mathrm{y}}\right)+21=6\left(\frac{\mathrm{x}}{\mathrm{y}}\right)+33$$$$9\left(\frac{\mathrm{x}}{\mathrm{y}}\right)=12$$$$\frac{\mathrm{x}}{\mathrm{y}}=\frac{12}{9}=\frac{4}{3}$$$$\mathrm{x}:\mathrm{y}=4:3$$

Commented by AHSoomro last updated on 26/Dec/17

$$ThanksB\mathrm{oss}$$

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