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Question Number 26712 by julli deswal last updated on 28/Dec/17

$$\mathrm{If}\mid x\mid <1,\mathrm{then}\mathrm{the}\mathrm{coefficient}\mathrm{of}{x}^n\mathrm{in}\mathrm{the}$$ $$\mathrm{expansion}\mathrm{of}{(1+x+x^2+x^3+x^4+...)}^2\mathrm{is}$$

Answered by mrW1 last updated on 28/Dec/17

$${(1+x+x^2+x^3+x^4+...)}^2=\underset{n=0}{\sum ^{\mathrm{\infty }}}(n+1)x^n$$

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