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Question Number 26733 by math solver last updated on 28/Dec/17

Commented by prakash jain last updated on 28/Dec/17

((3/2)x^3 −(1/(3x)))^9 =^9 C_i ((3/2))^i x^(2i) (−1)^(9−i) ((1/(3x)))^(9−i)   ^9 C_i ((3/2))^i (−1)^(9−i) ((1/3))^(9−i) x^(4i−9)   coeffcient of constant term  3i−9=0⇒i=3  ^9 C_2 ((3/2))^3 (−1)^(9−3) ((1/3))^(9−3)   =((9!)/(3!6!))×(3^3 /2^3 )×(1/3^6 )=((9×8×7)/(1×2×3))×(1/8)×(1/(3×9))=(7/(18))  3i−9=−3⇒i=2  2×((9!)/(2!7!))×(3^2 /2^2 )×(−1)^(9−2) ×(1/3^7 )=((9×8)/(4×3^5 ))=−(2/(27))  (7/(18))−(2/(27))=((17)/(54))

(32x313x)9=9Ci(32)ix2i(1)9i(13x)9i9Ci(32)i(1)9i(13)9ix4i9coeffcientofconstantterm3i9=0i=39C2(32)3(1)93(13)93=9!3!6!×3323×136=9×8×71×2×3×18×13×9=7183i9=3i=22×9!2!7!×3222×(1)92×137=9×84×35=227718227=1754

Answered by mrW1 last updated on 28/Dec/17

(1+x+2x^3 )((3/2)x^2 −(1/(3x)))^9   =(1/x^9 )(1+x+2x^3 )((3/2)x^3 −(1/3))^9     1×((9×8×7)/(3×2×1))×((3/2))^3 (−(1/3))^6 +2×((9×8)/(2×1))×((3/2))^2 (−(1/3))^7   =((3/2))^2 (−(1/3))^6 [1×((9×8×7)/(3×2×1))×((3/2))+2×((9×8)/(2×1))×(−(1/3))]  =((3/2))^2 (−(1/3))^6 (126−24)  =(1/2^2 )×(1/3^4 )×102  =((17)/(54))  ⇒Answer (A)

(1+x+2x3)(32x213x)9=1x9(1+x+2x3)(32x313)91×9×8×73×2×1×(32)3(13)6+2×9×82×1×(32)2(13)7=(32)2(13)6[1×9×8×73×2×1×(32)+2×9×82×1×(13)]=(32)2(13)6(12624)=122×134×102=1754Answer(A)

Commented by math solver last updated on 28/Dec/17

plz explain step−3?  how you find term independent of x?

plzexplainstep3?howyoufindtermindependentofx?

Commented by math solver last updated on 28/Dec/17

its something like  9_C_3   and 2. 9_C_7   .

itssomethinglike9C3and2.9C7.

Commented by mrW1 last updated on 28/Dec/17

x^0  term from (1/x^9 )(1+x+2x^3 )((3/2)x^3 −(1/3))^9   ≡x^9  term from (1+x+2x^3 )((3/2)x^3 −(1/3))^9   ≡1×x^9  term+x×x^8  term+2x^3 ×x^6  term    x^9  term of ((3/2)x^3 −(1/3))^9  is C_3 ^9 ×((3/2)x^3 )^3 ×(−(1/3))^6   there is no x^8  term in ((3/2)x^3 −(1/3))^9   x^6  term of ((3/2)x^3 −(1/3))^9  is C_2 ^9 ×((3/2)x^3 )^2 ×(−(1/3))^7     therefore the coefficient of x^0  term is  1× C_3 ^9 ×((3/2))^3 ×(−(1/3))^6 +2×C_2 ^9 ×((3/2))^2 ×(−(1/3))^7

x0termfrom1x9(1+x+2x3)(32x313)9x9termfrom(1+x+2x3)(32x313)91×x9term+x×x8term+2x3×x6termx9termof(32x313)9isC39×(32x3)3×(13)6thereisnox8termin(32x313)9x6termof(32x313)9isC29×(32x3)2×(13)7thereforethecoefficientofx0termis1×C39×(32)3×(13)6+2×C29×(32)2×(13)7

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