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Question Number 26864 by Tinkutara last updated on 30/Dec/17

	Answered by ajfour last updated on 31/Dec/17

	$i t h o u g h t o n e t h i r d o v e r h a n g e d .$ $N o w s i n c e o n e t h i r d p a r t l i e s o n$ $t a b l e i n i t i a l l y, w e c a n t h i n k t h i s$ $t r a n s m i t t e d t o j o i n t h e l o w e r$ $e n d o f t h e h a n g i n g p a r t b y t h e$ $t i m e i t s l i p s o f t h e t a b l e .$ $\frac{1}{2} {M v}^{2} = (\frac{M}{3}) g h$ $h i s s h i f t i n c e n t r e o f m a s s$ $o f t h e p a r t t h a t w a s o n t a b l e .$ $\frac{1}{2} (4) v^{2} = (\frac{4}{3}) (10) (\frac{4}{3} + \frac{1}{3})$ $\Rightarrow v^{2} = \frac{100}{9} o r v = \frac{10}{3} \frac{m}{s} .$
	Commented by Tinkutara last updated on 31/Dec/17
	Thank you very much Sir! I got the answer.
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