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Question Number 26909 by sorour87 last updated on 31/Dec/17
∫ex(1x−2x3)−2dx
Answered by prakash jain last updated on 31/Dec/17
∫ex(−12x+1x3)dx∫−ex2xdx+∫exx3dxintegratefirstbyparts=−ex2x−∫ex2x2dx+∫exx3dx=−ex2x−ex2x2−∫exx3dx+∫exx3dx=−ex(x+1)2x2
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