smlify X= Π_(p=2) ^n ((p^3 −1)/(p^3 +1)) by using 1,j,j^2 and j=e^((i2π)/3) .


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Question Number 26998 by abdo imad last updated on 01/Jan/18

$s m l i f y X = \prod_{p = 2}^{n} \frac{p^{3} - 1}{p^{3} + 1} b y u s i n g 1, j, j^{2} a n d j = e^{\frac{i 2 π}{3}} .$
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