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Question Number 27033 by Tinkutara last updated on 01/Jan/18

Answered by mrW1 last updated on 01/Jan/18

$${\left(\frac{L}{2h}\right)}^2=\frac{H}{H-h}=\frac{H}{H-\frac{3H}{4}}=4$$$$\Rightarrow L=4h$$

Commented by mrW1 last updated on 02/Jan/18

$$actuallyIusednophysicsformula.$$$$weknowtheprojectileisaparabola.$$$$inthecoordinatesystemshown$$$$belowwehave$$$$\frac{y_2}{y_1}={\left(\frac{x_2}{x_1}\right)}^2$$$$y_1=H-h=\frac{H}{4}$$$$y_2=H$$$$x_1=h$$$$x_2=\frac{L}{2}$$$$\Rightarrow 4={\left(\frac{L}{2h}\right)}^2$$$$\Rightarrow L=4h$$

Commented by mrW1 last updated on 02/Jan/18

Commented by Tinkutara last updated on 02/Jan/18

Thank you very much Sir! I got the answer.

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