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Question Number 27059 by math solver last updated on 01/Jan/18

Commented by prakash jain last updated on 01/Jan/18

$$1+z+z^2=x-xz+{xz}^2$$$$z^2(1-x)+z(1+x)+(1-x)=0$$$$\mathrm{Given}z\mathrm{is}\mathrm{not}\mathrm{real},\mathrm{root}\mathrm{are}$$$$\mathrm{complex}\mathrm{conjugate}$$$$\alpha =z,\beta =\overline{z}$$$$\mid z{\mid }^2=z\cdot \overline{z}=\alpha \cdot \beta =\frac{1-x}{1-x}=1$$

Commented by math solver last updated on 02/Jan/18

$$thankyousir!$$

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