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Question Number 27104 by ktomboy1992 last updated on 02/Jan/18

$${\sin 45}^o{\cos 45}^o+\sqrt{3\sin 60°=?}$$

Commented by mrW1 last updated on 02/Jan/18

$$whatdoyoumean?$$$${\sin 45}^o{\cos 45}^o+\sqrt{3}\sin 60°or$$$${\sin 45}^o{\cos 45}^o+\sqrt{3\sin 60°}?$$$$$$$${\sin 45}^o{\cos 45}^o+\sqrt{3}\sin 60°=\frac{1}{\sqrt{2}}\times \frac{1}{\sqrt{2}}+\sqrt{3}\times \frac{\sqrt{3}}{2}=\frac{1}{2}+\frac{3}{2}=\frac{4}{2}=2$$$${\sin 45}^o{\cos 45}^o+\sqrt{3\sin 60°}=\frac{1}{\sqrt{2}}\times \frac{1}{\sqrt{2}}+\sqrt{3\times \frac{\sqrt{3}}{2}}=\frac{1}{2}+\frac{\sqrt{6\sqrt{3}}}{2}=\frac{1+\sqrt{6\sqrt{3}}}{2}$$

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