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Question Number 27254 by tawa tawa last updated on 03/Jan/18

Answered by mrW1 last updated on 04/Jan/18

$$\left(a\right)$$$$\alpha =28.7-21.3=7.4°=\frac{7.4\pi }{180}\left[rad\right]$$$$\beta =38.6°$$$$R=6400km$$$$L_{PQ}=\alpha R\cos \beta =\frac{7.4\pi \times 6400\times \cos 38.6°}{180}=646km$$$$$$$$\left(b\right)$$$$\mathrm{\Delta }\beta =38.6-28.4=10.2°=\frac{10.2\pi }{180}\left[rad\right]$$$$L_{PT}=\mathrm{\Delta }\beta R=\frac{10.2\pi \times 6400}{180}=1140km$$$$$$$$\left(c\right)$$$$t=\frac{L}{v}=\frac{646+1140}{650}=2.75h=2h45m$$

Commented by tawa tawa last updated on 04/Jan/18

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}.\mathrm{I}\mathrm{really}\mathrm{appreciate}.$$

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