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Question Number 27334 by darkalestero1@gmail.com last updated on 05/Jan/18

$$\frac{{\mathrm{q}}_1}{{\mathrm{q}}_2}={\left(\frac{\mathrm{x}}{0.8-\mathrm{x}}\right)}^2;\mathbf{x}=?$$

Answered by mrW1 last updated on 05/Jan/18

$$\frac{x}{0.8-x}=\pm \sqrt{\frac{q_1}{q_2}}$$$$\frac{0.8-x}{x}=\pm \sqrt{\frac{q_2}{q_1}}$$$$\frac{0.8}{x}=1\pm \sqrt{\frac{q_2}{q_1}}$$$$\Rightarrow x=\frac{0.8}{1\pm \sqrt{\frac{q_2}{q_1}}}$$

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