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Question Number 27335 by bsayani309@gmail.com last updated on 05/Jan/18

if 2 chords of ellipse have the same  distance from the centre of ellipse  and the eccentric angle of the end points of the chords  are respectivly α β γ δ then prove that  tan (α/2)×tan (β/2)×tan (γ/2)×tan (δ/2)=1

$${if}\:\mathrm{2}\:{chords}\:{of}\:{ellipse}\:{have}\:{the}\:{same} \\ $$$${distance}\:{from}\:{the}\:{centre}\:{of}\:{ellipse} \\ $$$${and}\:{the}\:{eccentric}\:{angle}\:{of}\:{the}\:{end}\:{points}\:{of}\:{the}\:{chords} \\ $$$${are}\:{respectivly}\:\alpha\:\beta\:\gamma\:\delta\:{then}\:{prove}\:{that} \\ $$$$\mathrm{tan}\:\frac{\alpha}{\mathrm{2}}×\mathrm{tan}\:\frac{\beta}{\mathrm{2}}×\mathrm{tan}\:\frac{\gamma}{\mathrm{2}}×\mathrm{tan}\:\frac{\delta}{\mathrm{2}}=\mathrm{1} \\ $$

Commented by bsayani309@gmail.com last updated on 05/Jan/18

please give its answer

$${please}\:{give}\:{its}\:{answer} \\ $$

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