Question and Answers Forum

All Questions      Topic List

UNKNOWN Questions

Previous in All Question      Next in All Question      

Previous in UNKNOWN      Next in UNKNOWN      

Question Number 27397 by julli deswal last updated on 06/Jan/18

$$\mathrm{The}\mathrm{roots}\mathrm{of}{x}^2-(a+1)x+b^2=0\mathrm{are}$$$$\mathrm{equal}.\mathrm{Then}\mathrm{which}\mathrm{of}\mathrm{the}\mathrm{following}$$$$\mathrm{can}\mathrm{be}\mathrm{the}\mathrm{values}\mathrm{of}a\mathrm{and}b.$$

Answered by jota@ last updated on 06/Jan/18

$$a=1andb=1$$

Answered by mrW1 last updated on 06/Jan/18

$$\mathrm{\Delta }={(a+1)}^2-4b^2=0$$$$\Rightarrow a+1=\pm 2b$$$$\Rightarrow a=\pm 2b-1$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com