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Question Number 27419 by ayushrtet last updated on 06/Jan/18

(x^3 +5x^3 −2)/(x−1)

(x3+5x3−2)/(x−1)

Answered by Rasheed.Sindhi last updated on 06/Jan/18

(x^3 +5x^3 −2)/(x−1) (6x^3 −2)/(x−1) ((( 6x^2 +6x+6)),((x−1)6x^3 +0x^2 +0x−2 ^(−) )),(( 6x^3 −6x^2 _(−) )),(( 6x^2 +0x)),(( 6x^2 −6x _(−) )),(( 6x−2)),(( 6x−6 _(−) )),(( 4)) ) =6(x^2 +x+1)+(4/(x−1))

(x3+5x3−2)/(x−1)(6x3−2)/(x−1)Missing \left or extra \right=6(x2+x+1)+4x−1

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