Question Number 27436 by NECx last updated on 06/Jan/18
$${Car}\:{A}\:{is}\:{moving}\:{at}\:{a}\:{speed}\:{of}\: \\ $$$$\mathrm{45}{km}/{h}\:{towards}\:{car}\:{B}\:{which}\:{is} \\ $$$${moving}\:{towards}\:{car}\:{A}\:{at}\:{a}\:{speed}\: \\ $$$${of}\:\mathrm{55}{km}/{h}.{If}\:{the}\:{two}\:{cars}\:{where} \\ $$$${initially}\:{seperated}\:{at}\:{a}\:{distance} \\ $$$${of}\:\mathrm{150}{m}.{Determine}\:{how}\:{long}\:{it}\: \\ $$$${will}\:{take}\:{the}\:{two}\:{cars}\:{to}\:{meet}. \\ $$
Commented by Rasheed.Sindhi last updated on 07/Jan/18
$$\mathrm{150}{m}\:\mathrm{or}\:\mathrm{150}{km}? \\ $$
Answered by Rasheed.Sindhi last updated on 07/Jan/18
$$\mathrm{The}\:\mathrm{distance}\:\mathrm{is}\:\mathrm{covered}\:\mathrm{by}\:\left(\mathrm{45}+\mathrm{55}\right)\mathrm{km}/\mathrm{h} \\ $$$$=\mathrm{100}\:\mathrm{km}/\mathrm{h} \\ $$$$\begin{pmatrix}{\mathrm{Hours}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:}&{\mathrm{Kms}}\\{\:\:\:\:\:\:\:\mathrm{1}}&{\:\:\mathrm{100}}\\{\:\:\:\:\:\:\:\:\mathrm{x}}&{\:\:\:\mathrm{150}}\end{pmatrix} \\ $$$$\:\:\:\:\:\:\:\mathrm{x}=\frac{\mathrm{150}}{\mathrm{100}}=\mathrm{1}\frac{\mathrm{1}}{\mathrm{2}}\:\mathrm{hours} \\ $$
Commented by Arya last updated on 07/Jan/18
$${the}\:{unit}\:{is}\:{hour}\: \\ $$
Commented by Rasheed.Sindhi last updated on 07/Jan/18
$$\mathrm{Thanks}\:\mathrm{Arya}!\:\mathrm{Corrected}\:\mathrm{now}. \\ $$
Commented by NECx last updated on 07/Jan/18
$${thanks}\:.\:{I}\:{really}\:{appreciate}. \\ $$