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Question Number 27531 by sirigidiravikumar@gmail.com last updated on 08/Jan/18

$$\sqrt{1-\cos \theta /1+\cos \theta }=?$$

Commented by Rasheed.Sindhi last updated on 08/Jan/18

$$\sqrt{(1-\cos \theta )/(1+\cos \theta )}=?$$$$=\sqrt{\frac{1-\cos \theta }{1+\cos \theta }\times \frac{1-\cos \theta }{1-\cos \theta }}$$$$=\sqrt{\frac{{(1-\cos \theta )}^2}{1-{\cos }^2\theta }}$$$$=\sqrt{\frac{{(1-\cos \theta )}^2}{{\sin }^2\theta }}$$$$=\frac{1-\cos \theta }{\sin \theta }$$

Commented by sirigidiravikumar@gmail.com last updated on 08/Jan/18

thank you sir

Commented by abdo imad last updated on 08/Jan/18

$$\sqrt{\frac{1-cos\theta }{1+cos\theta }}=\sqrt{\frac{2{sin}^2\left(\frac{\theta }{2}\right)}{2{cos}^2\left(\frac{\theta }{2}\right)}}$$$$=/tan\left(\frac{\theta }{2}\right)/.$$

Commented by prakash jain last updated on 08/Jan/18

$$/\tan \frac{\theta }{2}/=\mid \tan \frac{\theta }{2}\mid$$$$\mathrm{Just}\mathrm{calrifying}\mathrm{since}\mathrm{some}\mathrm{new}$$$$\mathrm{users}\mathrm{may}\mathrm{not}\mathrm{be}\mathrm{aware}\mathrm{of}$$$$\mathrm{the}\mathrm{notation}\mathrm{that}\mathrm{you}\mathrm{are}\mathrm{using}.$$

Commented by abdo imad last updated on 08/Jan/18

$$thanksprakash...$$

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