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Question Number 27536 by darkalestero1@gmail.com last updated on 08/Jan/18

$${\mathbf{m}}_1{\mathbf{s}}_1(\mathbf{x}-\mathit{\theta })={\mathbf{m}}_2{\mathbf{s}}_2(\mathit{\theta }-\mathbf{y});\mathbf{x}=?;\mathbf{y}=?\mathit{\theta }=?$$$$\mathrm{solve}\mathrm{it}\mathrm{as}\mathrm{an}\mathrm{equation}....$$

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