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Question Number 27581 by Mcfaithal last updated on 10/Jan/18
Iff(x)=∫(4x−x2)dxf(3)=22,findf(x)
Answered by Joel578 last updated on 10/Jan/18
f(x)=∫4x−x2dx=2x2−13x3+Cf(3)=2(32)−13(33)+C=22→C=22−18+9=13f(x)=2x2−13x3+13
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