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Question Number 27663 by abdo imad last updated on 12/Jan/18
letgiveUn=n(1n2+112+n2+122+n2+....1(n−1)2+n2) findlimn−>∝Un.
Commented byabdo imad last updated on 13/Jan/18
wehaveUn=n∑k=0n−11k2+n2=1n∑k=0n−111+(kn)2 UnisaRiemansumand limn−>∝Un=limn−>∝1−0n∑k=0n−111+(k(1−0)n)2 =∫01dx1+x2=[arctanx]01=π4.
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